primitive_types5 solution

exercises/04_primitive_types/primitive_types5.rs

@@ -1,8 +1,8 @@
-// Destructure the `cat` tuple so that the println will work.
-
 fn main() {
     let cat = ("Furry McFurson", 3.5);
-    let /* your pattern here */ = cat;
 
-    println!("{} is {} years old.", name, age);
+    // TODO: Destructure the `cat` tuple in one statement so that the println works.
+    // let /* your pattern here */ = cat;
+
+    println!("{name} is {age} years old");
 }

rustlings-macros/info.toml

@@ -286,7 +286,7 @@ Particularly the part about destructuring (second to last example in the
 section).
 
 You'll need to make a pattern to bind `name` and `age` to the appropriate parts
-of the tuple. You can do it!!"""
+of the tuple."""
 
 [[exercises]]
 name = "primitive_types6"

solutions/04_primitive_types/primitive_types5.rs

@@ -1 +1,8 @@
-// Solutions will be available before the stable release. Thank you for testing the beta version 🥰
+fn main() {
+    let cat = ("Furry McFurson", 3.5);
+
+    // Destructuring the tuple.
+    let (name, age) = cat;
+
+    println!("{name} is {age} years old");
+}