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Simplify next_pending_exercise_ind
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@ -313,25 +313,22 @@ impl AppState {
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// Return the index of the next pending exercise or `None` if all exercises are done.
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fn next_pending_exercise_ind(&self) -> Option<usize> {
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if self.current_exercise_ind + 1 == self.exercises.len() {
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// The last exercise is done.
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// Search for exercises not done from the start.
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return self.exercises[..self.current_exercise_ind]
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.iter()
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.position(|exercise| !exercise.done);
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}
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// The done exercise isn't the last one.
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// Search for a pending exercise after the current one and then from the start.
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match self.exercises[self.current_exercise_ind + 1..]
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.iter()
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.position(|exercise| !exercise.done)
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{
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Some(ind) => Some(self.current_exercise_ind + 1 + ind),
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None => self.exercises[..self.current_exercise_ind]
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.iter()
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.position(|exercise| !exercise.done),
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}
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let next_ind = self.current_exercise_ind + 1;
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self.exercises
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// If the exercise done isn't the last, search for pending exercises after it.
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.get(next_ind..)
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.and_then(|later_exercises| {
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later_exercises
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.iter()
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.position(|exercise| !exercise.done)
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.map(|ind| next_ind + ind)
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})
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// Search from the start.
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.or_else(|| {
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self.exercises[..self.current_exercise_ind]
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.iter()
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.position(|exercise| !exercise.done)
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})
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}
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/// Official exercises: Dump the solution file form the binary and return its path.
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